Without actual division prove that 2x^3+13x^3+x-70 is divisible by x-2
Answers
Answered by
29
!! Question is Wrong !!
Now,
x-2=0
x=2
P(x) = 2x^3+13x^2+x-70
P(2) = 2(2)^3 + 13(2)^2 + 2 - 70
= 2×8 + 13×4 +2 - 70
= 16 + 52 + 2 - 70
= 70 - 70
= 0
SINCE P(x) = 0, 2x^3+13x^2+x-70 is divisible by x-2
Now,
x-2=0
x=2
P(x) = 2x^3+13x^2+x-70
P(2) = 2(2)^3 + 13(2)^2 + 2 - 70
= 2×8 + 13×4 +2 - 70
= 16 + 52 + 2 - 70
= 70 - 70
= 0
SINCE P(x) = 0, 2x^3+13x^2+x-70 is divisible by x-2
8847285090:
Thanx
Answered by
9
Step-by-step explanation:
P(x) = 2x^3+13x^2+x-70
P(2) = 2(2)^3 + 13(2)^2 + 2 - 70
= 2×8 + 13×4 +2 - 70
= 16 + 52 + 2 - 70
= 70 - 70
= 0
therefore 2x^3+13x^2+x-70 is divisible by (x-2)
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