without actual division, prove that 2x^4-5x^3+2x^2-x+2 is divisible by x^2-3x+2 .
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Answer:
First of all,
x^2-3x+2
=>x^2-2x-1x+2
=>x(x-2)-1(x-2)
=>(x-2)(x-1)
Therefore,(x-2)(x-1)are the factors.
i) (x-2)
x-2=0
=>x=2
So,p(x)=2
p(x)=2x^4-5x^3+2x^2-x+2
p(2)=2(2)^4-5(2)^3+2(2)^2-2+2
=32-40+8
= -40+40=0
Hence,it proves that (x-2) is a factor .
ii) (x-1)
=>x-1=0
=>x=1
So,p(x)=1
p(x)=2x^4-5x^3+2x^2-x+2
p(1)=2(1)^4-5(1)^3+2(1)^2-1+2
=2-5+2-1+2
=6-6=0
Hence,it proves that (x-1) is a factor.
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