Question

Without actual division prove that 2x^4-6x^3+3x^2+3x-2

Answer 1

Step-by-step explanation:

If P(x)=2x⁴–6x³+3x²+3x-2 is divisible by

g(x)=x²–3x+2=(x-2)(x-1) then

P(1)=0 and P(2)=0

P(1)=2–6+3+3–2=8–8=)

P(2)=2×16–6×8+3×4+3×2–2

=32–48+12+6–2=50–50=0

Therefore P(x) is divisible by g(x).

-----Hope this helps