Without actual division prove that the polynomial 2x^3+4x^2+x-34 is exactly divisible by (x-2)
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20
Hey!
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
Hence P ( X ) is Zero for X = 2 .
Therefore , it is divisible by ( X - 2 )
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Hence P ( X ) is Zero for X = 2 .
Therefore , it is divisible by ( X - 2 )
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Answered by
16
here is the answer......
mark as brainiest answer if you like.....
mark as brainiest answer if you like.....
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teju4739:
hey
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