Question

without actual division show that 23/200 is a recurring rational rational number​

Answer 1

The required answer is $\frac{23}{200}=0.115$.

Step-by-step explanation:

Consider the provided fraction $\frac{23}{200}$.

The above fraction can be written as:

$\frac{23}{200}=\frac{23}{2\times2\times2\times5\times5}=\frac{23}{2^3\times5^2}$

Now multiply and divide by 5.

$\dfrac{23}{2^3\times5^2}=\dfrac{23\times5}{2^3\times5^3}\\\\\dfrac{23}{2^3\times5^2}=\dfrac{115}{(2\times5)^3}\\\\\dfrac{23}{2^3\times5^2}=\dfrac{115}{(10)^3}\\\\\dfrac{23}{2^3\times5^2}=0.115$

Therefore, the required answer is $\frac{23}{200}=0.115$.

#Learn more

Convert the terminating decimal 75.35 as fraction​

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Answer 2

Answer:

Given above with best explanation.

23/300 = 0.0115