Question

without actual division,show that (x^3-3x^2-13+15) is exactly divisible by (x^2+2x-3) ​

Answer 1

Step-by-step explanation:

factoring x^2+2x-3

We have x^2+3x-x-3

x(x+3)-1(x+3)

so, x=1and-3

now putting value of X in equation if solution becomes zero then it is divisible by x^2+2x-3.