Question

Without actual long division determine whether (x - 2 ) is a factor of q(x ) = x 3 + 2x2 - 5x - 6

Answer 1

Answer:

x-2=0x=2

x3+2x2-5x-6

(2)3+2(2)×2-5(2)

8+8-10

16-6=10ans

Answer 2

(x - 2) is a factor of the expression $x^{3}+2x^{2}-5x-6$.

Step-by-step explanation:

The expression is $x^{3}+2x^{2}-5x-6$.

If (x - 2) is a factor of this expression then x = 2 will satisfy the equation $x^{3}+2x^{2}-5x-6=0$.

Substitute x = 2 in the above expression and check whether it equals to 0 or not as follows:

$x^{3}+2x^{2}-5x-6=(2^{3})+(2\times 2^{2})-(5\times 2)-6$

                            $=8+8-10-6\\=0$

Thus, (x - 2) is a factor of the expression $x^{3}+2x^{2}-5x-6$.

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