Question

Without actual long division determine whether (x-2) , (x+3) and (x-4) are factors of q(x)=x³+2x²-5x-6​

Answer 1

Answer:

(x-2)

x=2

x³+2x²-5x-6

(2)³+2(2)²-5(2)-6=

8+8-10-6=

16-16

0 Ans

(x+3)

x=-3

x³+2x²-5x-6

(3)³+2(3)²-5(3)-6

27+18-15-6

45-21

24Ans

(x-4)

x=4

x³+2x²-5x-6

(4)³+2(4)²-5(4)-6

64+32-20-6

96-26

70Ans

So, (x-2) it is a factor of (x³+2x²-5x-6)

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