Without actual multiplication , evaluate the following (a)10.2square (b)0.3square (c)58square
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let the two parts be x and yx + y = 29 ⇒ y = 29 - xso according to question x² + y² = 425⇒ x² + (29 - x)² = 425⇒ x² + 841 + x² - 58x = 425⇒2x² - 58x + 416 = 0⇒ x² - 29x + 208 = 0⇒ x² - 13x - 16x + 208 = 0⇒ x(x - 13) - 16(x - 13) = 0⇒ (x - 16)(x - 13) = 0 so x = 16 or 13 ANSWER
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