Question

without actual multiplying find the difference 82 square minus one square give me a solution

Answer 1

(82+1)(82-1)
(83)(81)
83+83+83+83+83+......81 times
6923

Answer 2

${82}^{2} - {1}^{2}$
$=( 82 + 1 )(82 - 1)$
$= (83)(81)$
$= 6723$
I hope this is correct and the formula here is -
${a}^{2} - {b}^{2}$
$= (a - b)(a + b)$
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