Question

Without actual squaring, find the value of:
() 23²-22
(ii) 101-100
(iii) 551²-500²​

Answer 1

ANSWER:

1-) 45

2-) 1

3-) 53601

step-by-step :

3. 551^2 -500^2 = a^2-b^2

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500)

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=53601

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)=(23+22)(23-22)

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)=(23+22)(23-22)=45x1

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)=(23+22)(23-22)=45x1=45

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)=(23+22)(23-22)=45x1=452). a-b

3. 551^2 -500^2 = a^2-b^2 = (a+b) (a-b)=(551+500)(551-500) =1051*51=536011) a^2-b^2 =(a+b)(a-b)=(23+22)(23-22)=45x1=452). a-b =1.......