without actually calculacting the cube find (-12)³+(7)³+(5)³
Answers
Answered by
4
a = -12
b = 7
c = 5
Here, a+b+c = -12 + 7 + 5 = -12+12 = 0
So, (-12)³ + 7³ + 5³ = 3 * (-12) * 7 * 5
= -1260
(: hope this help :)
b = 7
c = 5
Here, a+b+c = -12 + 7 + 5 = -12+12 = 0
So, (-12)³ + 7³ + 5³ = 3 * (-12) * 7 * 5
= -1260
(: hope this help :)
Fawzan10:
mark as brainliest plz....
Answered by
9
we can solve it by using the formula
a^3+b^3+c^3. =3abc
before this check that a+b+c=0
-12+7+5=
-12+12
=0
hence remainder =0
so (-12)³+(7)³+(5)³ = 3×-12×7×5
=-1260
=
a^3+b^3+c^3. =3abc
before this check that a+b+c=0
-12+7+5=
-12+12
=0
hence remainder =0
so (-12)³+(7)³+(5)³ = 3×-12×7×5
=-1260
=
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