Without actually calculate the cubes .
evaluate 14(3)+13(3)-27(3)
NOTE - 3 is not a no. it is cube
Answers
Answered by
4
14+13-27= 0
If a+b+c is zero then, a^3+b^3+c^3= 3abc
So, 14^3 + 13^3 - 27^3 = 3 × 14 × 13 × -27
= -14742
Hope it will help u....
( ´∀｀)
If a+b+c is zero then, a^3+b^3+c^3= 3abc
So, 14^3 + 13^3 - 27^3 = 3 × 14 × 13 × -27
= -14742
Hope it will help u....
( ´∀｀)
Answered by
3
Answer;
a^3+b^3+c^3=3abc
14^3+13^3-27^3=3*14*13*-27
=-14742
Step-by-step explanation:
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