Question

Without actually calculating the cube, Find the value of (0.3)^3+(-0.2)^3+(-0.1)^3

Answer 1

Step-by-step explanation:

(0+0.3)

$(0 + 0.3)^{3}$

$= \binom{3}{0} \times {0.1}^{5} \times {0.2}^{0} + \binom{3}{1} \times {0.1}^{2} \times {0.2}^{1} + \binom{3}{2} \times {0.1}^{1} \times {0.2}^{2} + \binom{3}{3} \times {0.1}^{0} \times {0.2}^{3}$

= 1 × 0.001 × 1 + 3 × 0.01 × 0.2 + 3 × 0.1 × 0.04 + 1 × 1 × 0.008