Question

without actually calculating the cube find the value of expression (28)³ +(-15)³+(-13)³​

Answer 1

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Answer 2

Answer:

i will give you a close hint.

suppose, 28,(-15),(-13) are a , b and c respectively.

here, a +b + c = (28-15-13) = 0

so,

( a³ + b³ + c³ – 3abc ) =>

(a+b+c)(a²+b²+c²-ab-bc-ca) [formula]

= 0 × (a²+b²+c²-ab-bc-ca) = 0

so, a³ + b³ + c³ = 3abc [as ( a³+b³+c³ -3abc )= 0]

so, 28³ + (-15)³ + (-13)³ = 3×28×(-15)×(-13} === calculate the value...

hope it helps...