Question

without actually calculating the cube find the value of 75^-25-50^3​

Answer 1

Answer:

281250

Step-by-step explanation:

if

a+b+c=0

a^3+b^3+c^3=3abc

75^3-25^3-50^3

(75)^3 +(-25)^3 + (-50)^3

Let

a=75 ,b = -25 ,c= -50

a+b+c=75+(-25)+(-50)

=75-25-50=75-75=0

a+b+c = 0

so

a^3+ b^3+c^3=3abc

(75)^3+(-25)^3+(-50)^3=3(75)(-25)(-50)

=281250

Answer 2

Step-by-step explanation:

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