Without actually calculating the cubes calculate 14^3+13^3-27^3
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Answered by
1
so required answer is -14742
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susheellattala:
i was doing the same in my copy LOL
late to take photo
oh
missing
anyways better luck next time
hmm
Answered by
2
Hi
Let
a=14 , b=13 , c=(-27)
if a+b+c=0
Then
=14+13+(-27)
=14+13-27
=0
If a^3+b^3+c^3=3abc
Thus, 14^3+13^3-27^3 = 3(14)(13)(-27)
=(-14742)
Let
a=14 , b=13 , c=(-27)
if a+b+c=0
Then
=14+13+(-27)
=14+13-27
=0
If a^3+b^3+c^3=3abc
Thus, 14^3+13^3-27^3 = 3(14)(13)(-27)
=(-14742)
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