Question

Without Actually calculating the cubes evaluate :
(28)^3+(-15)^3+(-13)^3

Answer 1

a=28
b= -15
c= -13
If a+b+c = 0 then a^3+b^3+c^3=3abc
a+b+c=28+(-15)+(-13)
a+b+c=0
Therefore,
a^3+b^3+c^3=3abc
28^3+(-15)^3+(-13)^3=3 (28)(-15)(-13)
=3×5460
=16380

Answer 2

We know that,

a³ + b³ + c³ = 3abc

now,

Let

a = 28

b = - 15

c = - 13

( 28 )³ + ( - 15 )³ + ( - 13 )³

= 3 ( 28 ) ( - 15 ) ( - 13 )

= 16380

thanks

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