Question

without actually calculating the cubes evaluate each of the following (1/4)3+(1/3)3-(7/12)3​

Answer 1

Answer:

$\huge\red{Answer}$

Answer 2

Answer:

We know that,

If (a+b+c)=0, then a^3  +b63  +c^3  =3abc  

Here, 28+(−15)+(−13)=0

∴(28)^3  +(−15)^3  +(−13)^3

=3(28)(−15)(−13)=16380