Without actually calculating the cubes. Evavulate 14^3+13^3-27^3
Attachments:
Answers
Answered by
1
1. (x-2)=0
x=2
2x^2+3x-k=0
2(2)^2+3×2-k=0
8+6-k=0
14-k=0
k=14
2. (2,3)=(x,y)
x=2
y=3
4y=ax+5
4×3=a×2+5
12=2a+5
7=2a
a=7/2
x=2
2x^2+3x-k=0
2(2)^2+3×2-k=0
8+6-k=0
14-k=0
k=14
2. (2,3)=(x,y)
x=2
y=3
4y=ax+5
4×3=a×2+5
12=2a+5
7=2a
a=7/2
Answered by
1
according to a Theorm..if (a+b+c) =0 then a^3+b^3+c^3=3abc.....therefore
14+13-27=0 so 14^3+13^3+27^3=3×14×13×-27......
=== -4914 is the answer
14+13-27=0 so 14^3+13^3+27^3=3×14×13×-27......
=== -4914 is the answer
Similar questions