Question

Without actually calculating the cubes find out
Please!!!.......................solve this problem​

Answer 1

a=(1/4)

b=(1/3)

c=(-7 /12)

a+b+c= 1/4 + 1/3 + 7/12

= 7/12 - 7/12

=0

if a+b+c =0, a^3+ b^3 +c^3 = 2abc

3*(1/4)*(1/3)*(7/12)

(1/4) * (7/12)

7/48

hope it helps.......

pls mark me brainliest and follow me

Answer 2

Step-by-step explanation:

a³+b³+c³= 3abc

if a+b+c=0

this is property

by verifying

we get that

1/4+1/3-7/12=0

so by using this property we get

= 3 ×1/4×1/3×7/12

= 7/48

thank you hope it helpful