without actually calculating the cubes, find the value a) (-12)³+(7)³+(5)²,b) (28)³+(15)³-(-13)³ please help
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Use the identity, a³+b³+c³=3ab.
a) (-12)³+(7)³+(5)³
=3(-12)(7)(5)
=-36*35
= -1260
b)(28)³+(15)³-(-13)³
=3(28)(15)(-13)
=84*-195
=-16380
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