Question

Without actually calculating the cubes find the value of each of the following
(28)power3+ (-15)power3+( -13) power3

Answer 1

= 28^3+(-15)^3+(-13)^3

=> If a+b+c =0 ,then we can do it by 3abc

(we are not taking powers i.e. a=28,b=-15,c=-13)

=28+(-15)+(-13)

=28-15-13

=0

=> 3abc

=3(28)(-15)(-13)

=16380

::answer is 16380

Hope this helps you

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