without actually calculating the cubes find the value of (-12)³+(10)³+(2)³
Answers
Answered by
0
Answer:
Heya user
Heya userHere is your answer !!
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abc
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abc
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)= -1260 (Ans)
Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)= -1260 (Ans)Hope it helps !!
Similar questions