Math, asked by nsmixf15lokesh, 6 hours ago

without actually calculating the cubes find the value of (-12)³+(10)³+(2)³​

Answers

Answered by ks78182k
0

Answer:

Heya user

Heya userHere is your answer !!

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abc

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abc

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)= -1260 (Ans)

Heya userHere is your answer !!(a+b+c)³ = a³ + b³ + c³ -3abcSo , if (a+b+c) is equal to 0 , then ,a³ + b³ + c³ = 3abcHere , (-12 + 7 + 5) = 0So , (-12)³+(7)³+(5)³ = 3(-12)(7)(5)= -1260 (Ans)Hope it helps !!

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