Question

without actually calculating the cubes find the value of 16^3-9^3-7^3

Answer 1

Answer:

3024

Step-by-step explanation:

You may know the formula a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

And if a+b+c = 0, then a³+b³+c³=3abc

Here, a=16 b=(-9) c=(-7)

And, a+b+c = 0

So, 16³-9³-7³ = 3 × 16 × (-9) × (-7) = 3024

Answer 2

Answer:

3024.please mark me as brainaliest