without actually calculating the cubes find the value of each of the following
Attachments:
Answers
Answered by
3
Answer:
- 1260
Step-by-step explanation:
(-12)^3 + (7)^3+(5)^3
here -12+7+5=0
we know a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^3+2ab+2bc+2ca)
but a+b+c=0
=> rhs = 0
=> a^3+b^3+c^3= 3abc
=3*-12*7*5
= - 1260
Brainliest plz
Similar questions
Physics,
4 months ago
Biology,
8 months ago
India Languages,
11 months ago
Hindi,
11 months ago
English,
11 months ago