Math, asked by krishnayadav5695, 8 months ago

Without actually calculating the cubes, find the value of each of the following:
(1) (-12)3+(7)3 + (5)3
(ii) (28)3 +(-15)3 +(-13)3;​

Answers

Answered by thestutimaurya
1

Answer:

Try to do 2nd like this..

Step-by-step explanation:

Hope ot will help you.

Attachments:
Answered by SpaceWalker17
3

QUESTION 1.

\bold{(-12)³+(7)³ + (5)³}

Consider

  • a = -12
  • b = 7
  • c = 5

Then,

\bold{a + b + c}

\bold{\leadsto -12 + 7 + 5}

\bold{\leadsto 0}

By using

a³ +b³ +c³=3abc

If a+b+c = 0

So,

\bold{(-12)³+(7)³ + (5)³}

\bold{\implies 3×(-12)×7×5}

\bold{\implies -1260}

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QUESTION 2.

\bold{(28)³+(-15)³ + (-13)³}

Consider

  • a = 28
  • b = -15
  • c = -13

Then,

\bold{a + b + c}

\bold{\leadsto 28 -15 -13}

\bold{\leadsto 0}

By using

a³ +b³ +c³=3abc

If a+b+c = 0

So,

\bold{(28)³+(-15)³ + (-13)³}

\bold{\implies 3×28×-15×-13}

\bold{\implies 16380}

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