Without actually calculating the cubes find the value of (25)^3 + (-16)^3 + (-9)^3
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We know that x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx). If x + y + z = 0, then x3 + y3 + z3 – 3xyz = 0 or x3 + y3 + z3 = 3xyz. We have to find the value of 483 – 303 – 183 = 483 + (–30)3 + (–18)3 . Here, 48 + (–30) + (–18) = 0 So, 483 + (–30)3 + (–18)3 = 3 × 48 × (–30) × (–18) = 77760Read more on Sarthaks.com - https://www.sarthaks.com/866995/without-actually-calculating-the-cubes-find-the-value-of-48-3-30-3-18-3
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