without actually calculating the cubes , find the value of 48cube-30cube-18cube
Anonymous:
ans is 6^5*10
how
first take 6^3 common from each term
than u can easily solve
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this is the answer hope it helps
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There is an identity in which
If a+b+c=0,then
a^3+b^3+c^3=3abc
(48)^3-(30)^3-(18)^3
48+(-30)+(-18)=0. (a+b+c=0)
=3abc
=3×48×-30×-18
=144×540
=77760
If a+b+c=0,then
a^3+b^3+c^3=3abc
(48)^3-(30)^3-(18)^3
48+(-30)+(-18)=0. (a+b+c=0)
=3abc
=3×48×-30×-18
=144×540
=77760
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