Without actually calculating the cubes, find the value of (27)cube +(-11)cube +(-10)cube
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Using the special identity
a^3+b^3+c^3=3abc
27^3+(-11)^3+(-10)^3 = 3(27)(-11)(-10)
= 8910
a^3+b^3+c^3=3abc
27^3+(-11)^3+(-10)^3 = 3(27)(-11)(-10)
= 8910
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