without actually calculating the cubes , find the value of (28)cube + (-15)cube + (-13)cube
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Let 28 be a
-15 be b
-13 be c
then
a+b+c=0
hence
a³+b³+c³=3abc
=3×(-15)(-13)(28)
=16380
-15 be b
-13 be c
then
a+b+c=0
hence
a³+b³+c³=3abc
=3×(-15)(-13)(28)
=16380
Shivarockstar499:
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