Without actually calculating the cubes, find the value of (30)3 + (–12)3 + (–18)3
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ANSWER ::
a = 30, b = - 12, c = - 18
So
a+b+c = 0
Then
a³ + b³ + c³ = 3abc
(30)³ + (-12)³ +) - 18)³ = 3×30×(-12)×(-18) = 19440
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