Without actually calculating the cubes, find the value of each of the following: (i) (28)+(-15)+(-13)j
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Answer:
28³+(-15)³+(-13)³-3abc=(28-28)(a²+b²+c²-1(ab+bc+ca)
28³-15³-13³-3abc=0
28³-15³-13³=3abc
28³-15³-13³=3×28×-15×-13
=16,380 Answer
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