Question

Without actually calculating the cubes , find the value of 48^3 - 30^3 - 18^3

Answer 1

if a+b+c=0 then a^3+b^3+c^3=3abc
48+(-30)+-(18)=0
48^3+30^3-18^3=3*48*-30*-18
=77760

Answer 2

Answer:

Value of 48³-30³-18³ = 77760

Step-by-step explanation:

/*By algebraic identity:

$If \: x+y+z=0 \: then \: \\</p><p>x^{3}+y^{3}+z^{3}=3xyz$

Here ,

Given ,

48³ - 30³ - 18³

= (48)³ + (-30)³ + (-18)³

x=48,y=-30, z = -18

Now ,

x+y+z

= 48+(-30)+(-18)

= 48-30-18

= 48-48

= 0

Therefore,

48³ + (-30)³+ (-18)³

= 3xyz

= 3(48)(-30)(-18)

= 77760

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