without actually calculating the cubes find the value of (48)³-(30)³-(18)³
Answers
Answered by
88
48-30-18=0
so using identity,
a^3+b^3+c^3 when a+b+c=o then it is equal to 3abc
putting the values ,
3× 48×(-30)×(-18)
777600.
so using identity,
a^3+b^3+c^3 when a+b+c=o then it is equal to 3abc
putting the values ,
3× 48×(-30)×(-18)
777600.
ShivamSingh11111:
answer is wrong...
she took 48 as 40
srry vo by mistake ho gya tha
its okay thanks allysia
Answered by
95
As you can see they are in the form of a³ +b³ +c³
By using the alzebric identity
a³+b³+c³ = 3abc.
We can simply sovle it.
so let
a³ = 48³
b³ = -30³
and
c³ = -18³
So, they could be written as
48³ +(-30)³ +(-18)³ = 3(48)(-30)(-18)
which equals, 77,760.
By using the alzebric identity
a³+b³+c³ = 3abc.
We can simply sovle it.
so let
a³ = 48³
b³ = -30³
and
c³ = -18³
So, they could be written as
48³ +(-30)³ +(-18)³ = 3(48)(-30)(-18)
which equals, 77,760.
thanks
my solution is little bit more laandy .....
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