without actually calculating the cubes , find the value of 50^3-30^3-20^3
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a+b+c=0 so,we put 3xyz where x= 50, y= -30 and z=-20 then answer =30000
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50^3 - 30^3 - 20^3
=(30+20)^3 - 30^3 - 20^3 ((a+b)^3 -a^3 - b^3)
=3x30x20(30+20) (=3ab(a+b))
=90000(Ans)
=(30+20)^3 - 30^3 - 20^3 ((a+b)^3 -a^3 - b^3)
=3x30x20(30+20) (=3ab(a+b))
=90000(Ans)
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