Question

Without actually calculating the cubes find the value of 55^3-25^3-30^3

Answer 1

Answer:

we know that,

X+y+z=0,

x^3+y^3+z^3=3xyz

according to the question,

let X=55, Y=-25 and Z=-30

X+y+z=55+(-25)+(-30)

=55-25-30

=55-55

=0

so, X+y+z=0

therefore, x^3+y^3+z^3=3xyz

=55^3+(25)^3+(-30)^3

=3×55×-25×-30

=165×750

Ans =123750

Answer 2

Answer:

Step-by-step explanation:

I hope it helps