Without actually calculating the cubes find the value of
a)483- 303 – 183
b) (x-y)3 +(y-z)+(2-x)3
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Step-by-step explanation:
by using formulae
x^3+y^3+z^3-3xyz=0
x^3+y^3+z^3=3xyz
let x=483,y=-303,z=-183
=3×483×-303×-183
=80345601
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