Math, asked by jademarcle, 1 year ago

Without actually calculating the cubes find the value of
a)483- 303 – 183
b) (x-y)3 +(y-z)+(2-x)3

Answers

Answered by prakriti48
2

Step-by-step explanation:

by using formulae

x^3+y^3+z^3-3xyz=0

x^3+y^3+z^3=3xyz

let x=483,y=-303,z=-183

=3×483×-303×-183

=80345601

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