Question

Without actually calculating the cubes, find the value of
$( \frac{1}{2} ) {}^{3} +( \frac{1}{3} ) {}^{3} + ( \frac{ - 5}{6} ) {}^{3}$
​

Answer 1

Answer:

$( \frac{1}{2} )^{3} + (\frac{1}{3} ) ^{3} + ( \frac{ - 5}{6} ) ^{3} \\ \\ \\ = > \frac{1}{8} + \frac{1}{27} - \frac{125}{216} \\ \\ \\ = > \frac{27 + 8 - 125}{216} \\ \\ \\ > \frac{ - 90}{216} \\ \\ = > \frac{ - 45}{208}$

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