Question

without actually calculating the cubes, find the values {i} (-28)3 + (15)3 + (13)3​

Answer 1

Question:

Without actually calculating the cubes, find the value of 28³ + (-15)³ + (13)³.

Answer:

Let a = 28, b = -15 and c = -13, then

a + b + c = 28 - 15 - 13 = 0

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We know that if a + b + c = 0,

then a³ + b³+ c³ = 3abc

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Putting back the values of a, b and c in a³ + b³ + c³ = 3abc

\therefore∴ 28³ + (-15)³ + (-13)³ = 3(28)(-15)(-13)

= 84\times× 195

= 16380.

i hope it helps you pls mark it as brainliest

Answer 2

wow it's very helpful for me in future, thanks a lot