without actually calculating the cubes find the volume of each of the following
(28^ 3 + - 15 + - 13)
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(28)3 + (-15)3 + (-13)3 Let x = 28, y = −15, and z = −13 It can be observed that, x + y + z = 28 + (−15) + (−13) = 28 − 28 = 0 It is known that if x + y + z = 0, then X3 + Y3 +Z3 (28)3 + (-15)3 + (-13)3 = 3(28) + (-15) + (-13) = 16380
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