Without actually calculating the cubes,fond the value of (28)^3 + (-15)^3 + (-13)^3
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Let a = 28
b = -15
and, c = -13
so, a + b + c = 28 - 15 - 13 = 0
We know that if a+ b + c = 0 then a³ + b³ + c³ = 3abc
So, (28)^3 + (-15)^3 + (-13)^3 = 3*28*-15*-13 = 16380
b = -15
and, c = -13
so, a + b + c = 28 - 15 - 13 = 0
We know that if a+ b + c = 0 then a³ + b³ + c³ = 3abc
So, (28)^3 + (-15)^3 + (-13)^3 = 3*28*-15*-13 = 16380
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