Question

without actually calculating the cubic, evaluate: (24)^3-(-13)^3-(-11)^3​

Answer 1

a=24

b=-13

c=-11

a+b+c=24-11-13

=0

Since a+b+c=0

therefore a^3+b^3+c^3=3abc

(24)^3+(-11)^3+(-13)^3=3×24×(-11)×(-13)

=10296

Hope it helps you.

Please mark it as brainliest.

Answer 2

Hey mate!!

Answer:-

$24{}^{3}-(-13){}^{3}-(-11){}^{3}=3(24)(-13)(-11)$

Without actually calculating cube

we use the formula:-

$a{}^{3}+b{}^{3}+c{}^{3}=3abc$

a=24

b=(-13)

c=(-11)

3(24)(-13)(-11)

72×143

✅=10,296

✌✌Hope its help uh✌✌