without actually calucating cube, evaluate 10³+11³-21³
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Answered by
1
10 ^3 +11^3 -21^3
= (10+11) ^3 - 21^3
=21^3 - 21^3
=0
= (10+11) ^3 - 21^3
=21^3 - 21^3
=0
Shiksha04:
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Answered by
0
a+b+c=0
so a^3+b^3+c^3=3abc
3×11×-21×10=-6930
so a^3+b^3+c^3=3abc
3×11×-21×10=-6930
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