Question

without actually finding the zeroes of polynomial f(x)= 3(x²-1)+2x-5 find sum and product of zeroes
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Answer 1

Answer:

-2/3, -8/3

Step-by-step explanation:

Given Equation is f(x) = 3(x² - 1) + 2x - 5

⇒ 3x² - 3 + 2x - 5

⇒ 3x² + 2x - 8.

Zeroes of the polynomial is f(x) = 0.

⇒ 3x² + 2x - 8 = 0.

On comparing with ax² + bx + c = 0, we get

a = 3, b = 2, c = -8.

Now,

(i) Sum of zeroes:

= -b/a

= -2/3

(ii) Product of zeroes:

= c/a

= -8/3

Hope it helps!

Answer 2

Given Equation is f(x) = 3(x² - 1) + 2x - 5

⇒ 3x² - 3 + 2x - 5

⇒ 3x² + 2x - 8.

Zeroes of the polynomial is f(x) = 0.

⇒ 3x² + 2x - 8 = 0.

On comparing with ax² + bx + c = 0, we get

a = 3, b = 2, c = -8.

Now,

(i) Sum of zeroes:

= -b/a

= -2/3

(ii) Product of zeroes:

= c/a

= -8/3

Hope it helps!

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