Without actually performing long division ,state why 129/6^2×5^3 is a non terminating repeating decimal expansion.
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cos the denomenator contains 6 and 3
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Fractions or rational numbers have terminating decimal expansion if and only if their denominator can be expressed as 5^a × 2^b.
But the given number's denominator has a factor of 6^2, that is, 2^2 × 3^2.
Hence it has a non terminating decimal expansion
But the given number's denominator has a factor of 6^2, that is, 2^2 × 3^2.
Hence it has a non terminating decimal expansion
varshabhade7:
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