Question

Without acutually calculating the cubes find the value of 27^3+(-17)^3+(-10)^3

Answer 1

so if
x+y+z=0
then
$x^3 + y^3 + z^3 = 3xyz$

$27 + (-17) + (-10) =0$

$0=0$

$27^3 + (-17)^3 + (-10)^3 = 3(27)(17)(10)$

$=13770$

Answer 2

Answer:

Step-by-step explanation:

Let x=27,y=-17,z=-10

X+y+z

That is,

=27+(-17)+-10

=27+(-27)=0

If x+y+z=0,

x^3+y^3+z^3=3xyz.

Therefore,27^3+(-17)^3+(-10)^3=3×27×-17×-10

=13770

HOPE IT HELPED YOU PLS MARK AS BRAINLIEST