Question

Without adding fimd the sum of 1+3+5+7+9+11+13+15+17+19+21

please help me


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Answer 1

ANSWER

The sum of an Arithmetic progression = 121, 

Let the first number be 1 as it is the smallest odd number.

Then, common difference = 2

Sum of an arithmetic progression = 2n×(2a+(n−1)d) = 121

2n×(2×1+(n−1)×2) = 121

2n×2n=121

n2=121

Thus n=11

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Answer 2

Step-by-step explanation:

answer is 121 ok mark me as brainlisenst