Math, asked by vimalasenthilds, 6 hours ago

without adding find the some of 1+3+5+7+9+11+13+15+17+19+21

Answers

Answered by Anonymous

12

1+3+5+7+9+11+13+15+17+19+21

1+3+5+7+9+11+13+15+17+19+21Since, there are 12 consecutive odd numbers, Thus, their sum = 11^2

=121

Answered by manzoorsaddah

1

Answer:

121 is the correct answer

hope it helpz u! ♥

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