Without adding, find the sum (a) 2+ 3+ 5+ 7+ 9 +11+ 13
show the process and proof also please!!
Answers
Answered by
2
Answer:
49
Step-by-step explanation:
take no. of digits = n
now square it so n = 7
so the square of 7 is 49
so answer is 49
now subtract n from it
so answer is 42
Hope it helps you ;)
Answered by
1
Answer:
Given 2+ 3+ 5+ 7+ 9 +11+ 13
we can write given sum as
=1+[1+3+5+7+9+11+13]
=1+[7²]. (sum of n odd numbers starting from 1 is =n²)
=1+49
=50.
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